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您的位置：首页 → 精文荟萃 → 破解文章 → 算法——极限信息发布器 V1.0
算法——极限信息发布器 V1.0
时间：2004/10/15 0:56:00来源：本站整理作者：蓝点我要评论(0)
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下载页面： http://www.seekeasysoft.com/maxinfo/maxinfo.htm
英文名称：MaxInfo
当前版本：V 1.0
maxinfo.exe无壳。DELPHI编写。反汇编，查找关键提示。
序列号：206540629
试炼码：13572468
—————————————————————————————————
* Possible StringData Ref from Code Obj ->"00000000"
|
:0048BE3E BA5CBF4800 mov edx, 0048BF5C
:0048BE43 E8DC88F7FF call 00404724
:0048BE48 8D4DF4 lea ecx, dword ptr [ebp-0C]
* Possible StringData Ref from Code Obj ->"请输入您的软件注册码"
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:0048BE4B BA70BF4800 mov edx, 0048BF70
* Possible StringData Ref from Code Obj ->"登记注册"
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:0048BE50 B890BF4800 mov eax, 0048BF90
:0048BE55 E8A2B5FAFF call 004373FC
:0048BE5A 3C01 cmp al, 01
:0048BE5C 0F85C8000000 jne 0048BF2A
:0048BE62 8D55E0 lea edx, dword ptr [ebp-20]
:0048BE65 8B45F4 mov eax, dword ptr [ebp-0C]
:0048BE68 E8FBCAF7FF call 00408968
:0048BE6D 8B45E0 mov eax, dword ptr [ebp-20]
====>EAX=13572468
:0048BE70 E8C7CDF7FF call 00408C3C
====>将试炼码转化成16进制表示
:0048BE75 8945F8 mov dword ptr [ebp-08], eax
====>EAX=CF1974
CF1974 是我们输入的数字 13572468 的16进制值！
:0048BE78 8955FC mov dword ptr [ebp-04], edx
:0048BE7B 6A00 push 00000000
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:0048BE0C(C)
|
:0048BE7D 6A4C push 0000004C
====>4C
:0048BE7F 8B45F8 mov eax, dword ptr [ebp-08]
====>EAX=CF1974
:0048BE82 8B55FC mov edx, dword ptr [ebp-04]
:0048BE85 E8EA97F7FF call 00405674
====>关键CALL！进入！
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
进入 48BE85 call 00405674
* Referenced by a CALL at Addresses:
|:0040F780 , :0048BE85
|
:00405674 55 push ebp
:00405675 53 push ebx
:00405676 56 push esi
:00405677 57 push edi
:00405678 31FF xor edi, edi
:0040567A 8B5C2414 mov ebx, dword ptr [esp+14]
====>4C 入 EBX
:0040567E 8B4C2418 mov ecx, dword ptr [esp+18]
:00405682 09C9 or ecx, ecx
:00405684 7508 jne 0040568E
:00405686 09D2 or edx, edx
:00405688 745C je 004056E6
:0040568A 09DB or ebx, ebx
:0040568C 7458 je 004056E6
…… …… 省 略 …… ……
* Referenced by a (U)nconditional or (C)onditional Jump at Addresses:
|:00405688(C), :0040568C(C)
|
:004056E6 F7F3 div ebx
====>EAX= CF1974/4C = 2B999
:004056E8 31D2 xor edx, edx
:004056EA EBF3 jmp 004056DF
:004056EC C3 ret
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
:0048BE8A 8945F8 mov dword ptr [ebp-08], eax
:0048BE8D 8955FC mov dword ptr [ebp-04], edx
:0048BE90 8B45F8 mov eax, dword ptr [ebp-08]
====>EAX =2B999
:0048BE93 8B55FC mov edx, dword ptr [ebp-04]
:0048BE96 2D40BB0000 sub eax, 0000BB40
====>EAX =2B999-BB40=1FE59
:0048BE9B 83DA00 sbb edx, 00000000
:0048BE9E 8945F8 mov dword ptr [ebp-08], eax
====>1FE59 入 [ebp-08] 下面比较用
:0048BEA1 8955FC mov dword ptr [ebp-04], edx
:0048BEA4 8D45E4 lea eax, dword ptr [ebp-1C]
:0048BEA7 E8B833FFFF call 0047F264
====>关键CALL！进入！
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
进入 48BEA7 call 0047F264
* Referenced by a CALL at Addresses:
|:0048B141 , :0048BEA7
|
:0047F264 53 push ebx
:0047F265 57 push edi
:0047F266 89C7 mov edi, eax
:0047F268 B801000000 mov eax, 00000001
:0047F26D 0FA2 cpuid
====>？EAX=F13
呵呵，请教 CPUID 是什么意思呀？为何一过此EAX就=F13？
:0047F26F AB stosd
:0047F270 89D8 mov eax, ebx
:0047F272 AB stosd
:0047F273 89C8 mov eax, ecx
:0047F275 AB stosd
:0047F276 89D0 mov eax, edx
:0047F278 AB stosd
:0047F279 5F pop edi
:0047F27A 5B pop ebx
:0047F27B C3 ret
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
:0048BEAC 8B4DE4 mov ecx, dword ptr [ebp-1C]
====>F13 入 ECX
:0048BEAF 8BC1 mov eax, ecx
====>EAX=ECX=F13
:0048BEB1 99 cdq
:0048BEB2 3B55FC cmp edx, dword ptr [ebp-04]
:0048BEB5 755E jne 0048BF15
:0048BEB7 3B45F8 cmp eax, dword ptr [ebp-08]
====>比较了！
====>EAX=F13
====>[ebp-08]=1FE59
:0048BEBA 7559 jne 0048BF15
====>跳则OVER！
:0048BEBC 33D2 xor edx, edx
:0048BEBE 8B83E8030000 mov eax, dword ptr [ebx+000003E8]
:0048BEC4 8B08 mov ecx, dword ptr [eax]
:0048BEC6 FF5164 call [ecx+64]
:0048BEC9 B201 mov dl, 01
:0048BECB 8B83F4020000 mov eax, dword ptr [ebx+000002F4]
:0048BED1 8B08 mov ecx, dword ptr [eax]
:0048BED3 FF5164 call [ecx+64]
* Possible StringData Ref from Code Obj ->"已注册登记版本"
|
:0048BED6 BAA4BF4800 mov edx, 0048BFA4
:0048BEDB 8B83E4030000 mov eax, dword ptr [ebx+000003E4]
:0048BEE1 E84E20FBFF call 0043DF34
:0048BEE6 33D2 xor edx, edx
:0048BEE8 8B83F0030000 mov eax, dword ptr [ebx+000003F0]
:0048BEEE E84120FBFF call 0043DF34
:0048BEF3 8B83F4030000 mov eax, dword ptr [ebx+000003F4]
:0048BEF9 E84627FFFF call 0047E644
:0048BEFE 6A00 push 00000000
:0048BF00 668B0DB4BF4800 mov cx, word ptr [0048BFB4]
:0048BF07 B202 mov dl, 02
* Possible StringData Ref from Code Obj ->"软件登记注册成功"
====>呵呵，胜利女神！
:0048BF09 B8C0BF4800 mov eax, 0048BFC0
:0048BF0E E8CDB3FAFF call 004372E0
:0048BF13 EB15 jmp 0048BF2A
* Referenced by a (U)nconditional or (C)onditional Jump at Addresses:
|:0048BEB5(C), :0048BEBA(C)
|
:0048BF15 6A00 push 00000000
:0048BF17 668B0DB4BF4800 mov cx, word ptr [0048BFB4]
:0048BF1E B201 mov dl, 01
* Possible StringData Ref from Code Obj ->"软件注册号错误"
====>BAD BOY！
—————————————————————————————————
【算 法 总 结】：
真码=（F13+BB40）*4C=3C10A4（H）=3936420（D）
请教一下：4B79CD cpuid ？EAX=544是如何得出的？
—————————————————————————————————
【注册信息保存】：
REGEDIT4
[HKEY_LOCAL_MACHINE\Software\CLASSES\CLSID\{1AE69D60-73D0-11D4-BD52-38A480C50000}]
"812181690"="812181690"
—————————————————————————————————
【整 理】：
序列号：206540629
注册码：3936420
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